闡明理由

闡明理由 pdf epub mobi txt 電子書 下載2025

出版者:復旦大學齣版社
作者:[美] 羅伯特·布蘭頓
出品人:
頁數:0
译者:陳亞軍
出版時間:
價格:45
裝幀:平裝
isbn號碼:9787309143287
叢書系列:實用主義與美國思想文化譯叢
圖書標籤:
  • 哲學 
  • 布蘭頓 
  • 實用主義 
  • 羅伯特·布蘭頓著作集 
  • 羅伯特·布蘭頓及其研究 
  • 實用主義與美國思想文化譯叢 
  • 匹茲堡學派 
  • 分析哲學 
  •  
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算是解答瞭我許久以來的睏惑:Given ψ⇒φ, it may be the case that p&q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?

评分

算是解答瞭我許久以來的睏惑:Given ψ⇒φ, it may be the case that p&q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?

评分

算是解答瞭我許久以來的睏惑:Given ψ⇒φ, it may be the case that p&q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?

评分

算是解答瞭我許久以來的睏惑:Given ψ⇒φ, it may be the case that p&q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?

评分

算是解答瞭我許久以來的睏惑:Given ψ⇒φ, it may be the case that p&q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?

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