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算是解答了我许久以来的困惑：Given ψ⇒φ, it may be the case that p＆q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?
评分算是解答了我许久以来的困惑：Given ψ⇒φ, it may be the case that p＆q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?
评分算是解答了我许久以来的困惑：Given ψ⇒φ, it may be the case that p＆q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?
评分算是解答了我许久以来的困惑：Given ψ⇒φ, it may be the case that p＆q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?
评分算是解答了我许久以来的困惑：Given ψ⇒φ, it may be the case that p＆q⇒p or p⇒p∨q. Always the question arises: how can we rule out the possibility of the former when what we actually assert is the latter in form of ψ⇒φ ?
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